x^4-9x^2+48=0

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Solution for x^4-9x^2+48=0 equation:


Simplifying
x4 + -9x2 + 48 = 0

Reorder the terms:
48 + -9x2 + x4 = 0

Solving
48 + -9x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + -9x2 + -48 + x4 = 0 + -48

Reorder the terms:
48 + -48 + -9x2 + x4 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + -9x2 + x4 = 0 + -48
-9x2 + x4 = 0 + -48

Combine like terms: 0 + -48 = -48
-9x2 + x4 = -48

The x term is -9x2.  Take half its coefficient (-4.5).
Square it (20.25) and add it to both sides.

Add '20.25' to each side of the equation.
-9x2 + 20.25 + x4 = -48 + 20.25

Reorder the terms:
20.25 + -9x2 + x4 = -48 + 20.25

Combine like terms: -48 + 20.25 = -27.75
20.25 + -9x2 + x4 = -27.75

Factor a perfect square on the left side:
(x2 + -4.5)(x2 + -4.5) = -27.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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